(x^2-3x)^2-22(x^2-3x)+72=0

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Solution for (x^2-3x)^2-22(x^2-3x)+72=0 equation: 



(x^2-3x)^2-22(x^2-3x)+72=0

We multiply parentheses

-22x^2+(x^2-3x)^2+66x+72=0

We add all the numbers together, and all the variables

-22x^2+66x+(x^2-3x)^2+72=0

We move all terms containing x to the left, all other terms to the right

-22x^2+66x+(x^2-3x)^2=-72

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